The JSON value could not be converted to System.String. Path: $.createdAt | LineNumber: 0 | BytePositionInLine: 10.: what it means and how to fix it

TL;DR: Validate locally, fix the first real error, validate again (no upload).

Troubleshoot The JSON value could not be converted to System.String. Path: $.createdAt | LineNumber: 0 | BytePositionInLine: 10. quickly and validate JSON locally (no upload).

What the error means

The JSON value could not be converted to System.String. Path: $.createdAt | LineNumber: 0 | BytePositionInLine: 10. usually means the JSON was parsed, but the value at some path does not match the type/schema your code expects (for example: array vs object, number vs string, null vs non-nullable).

Most common real-world causes

  • Your code expects a different type (number vs string, bool vs string, object vs array).
  • A field is null/missing but your type is non-nullable (or your code assumes it is always present).
  • The API response shape changed (or differs by environment / feature flags).
  • You are deserializing the wrong endpoint or the response is an error payload with a different schema.
  • Date/UUID/IP formats don't match what the deserializer expects.

Fast debugging steps

  • Parse into a generic JSON type first (Value/JToken/JsonElement/JsonNode) and inspect the actual shape at the failing path.
  • Confirm whether the field is an array vs object and whether scalars are strings vs numbers.
  • Add defensive handling for null/missing fields (optional types, defaults, or custom converters).
  • Log the raw response (or a redacted sample) and validate it locally to rule out truncation or hidden prefixes.
  • Update DTO/types to match the real response shape (or use a more flexible model for unstable fields).

Code example (csharp)

using System;
using System.Text.Json;

// 1) Parse into JsonElement to inspect the real shape first
using var doc = JsonDocument.Parse(text);
var root = doc.RootElement;

// 2) Inspect suspicious paths (example)
if (root.TryGetProperty("value", out var value)) {
  Console.WriteLine(value.ValueKind);
  Console.WriteLine(value.ToString());
}

// 3) Only then deserialize into a strong type
// var model = JsonSerializer.Deserialize<MyDto>(text);

Fix without uploading data

If the JSON contains sensitive data, validate and fix it locally. No Upload Tools runs 100% in your browser.

Workflow: validate -> fix the first error -> validate again -> export/convert.

FAQ

Does this mean the JSON is invalid? Not necessarily. Many of these errors happen when the JSON is valid, but your code expects a different type/shape.

What is the fastest fix? Parse into a generic JSON type first (Value/JToken/JsonElement/JsonNode), inspect the failing path, then update your DTO/type (or add a converter) to match the real response.

Privacy & Security
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Запрос из поиска

go yaml: line 2: mapping values are not allowed in this context

  • Проверьте структуру и типы входных данных.
  • Найдите позицию ошибки и изолируйте минимальный пример.
  • Сверьте экранирование, разделители и кодировку.
  • Примените фикс и повторите проверку на реальном payload.

Quick fix checklist

  • Reproduce the error on a minimal input.
  • Check type/format and field mapping.
  • Apply the smallest safe fix.
  • Validate on production-like payload.

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